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  • A crystal is doped with <img alt="10^{22} \text { boron atoms } / \mathrm{m}^3 \text {. }" src="https://entrancecorner.oncodecogs.com/gif.latex?10%5E%7B22%7D%20%5Ctext%20%7B%20boron%20atoms%20%7D%2

A crystal is doped with 10^{22} \text { boron atoms } / \mathrm{m}^3 \text {. } If the intrinsic carrier concentration is 5\times 10^{16}m^{-3} 

at room temperature, what is the excess carrier concentration?

 

Option: 1

8.5 \times 10^{12} \mathrm{~m}^{-3} \\


Option: 2

2.5 \times 10^7 \mathrm{~m}^{-3} \\


Option: 3

5 \times 10^7 \mathrm{~m}^{-3} \\


Option: 4

8.5 \times 10^{16} \mathrm{~m}^{-3}


Answers (1)

best_answer

The excess carrier concentration can be calculated as \left(n_d-n_i\right)=\left(10^{22} \mathrm{~m}^{-3}-5 \times 10^{16} \mathrm{~m}^{-3}\right)=8.5 \times 10^{12} \mathrm{~m}^{-3}  where n_{d} is the donor concentration and n_{i} is the intrinsic carrier concentration.

 

Posted by

Divya Prakash Singh

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