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A diode is connected to 220 V (rms)ac in series with a capacitor as shown in figure. The voltage across the capacitor is

Option: 1

\mathrm{220\ V}


Option: 2

\mathrm{110\ V}


Option: 3

\mathrm{311.1\ V}


Option: 4

\mathrm{\frac{220}{\sqrt{2}} V}


Answers (1)

best_answer

The diode \mathrm{D} will conduct for positive half cycle of \mathrm{a. c.} supply because this is forward biased. For negative half cycle of \mathrm{a. c.} supply, this is reverse biased and does not conduct. So out put would be half wave rectified and for half wave rectified out put
\mathrm{V_{r m s}=\frac{V_0}{2}=\frac{200 \sqrt{2}}{2}=\frac{200}{\sqrt{2}}}

Posted by

Divya Prakash Singh

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