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A dipole is placed in an electric field as shown. In which direction will it move?


 

Option: 1

towards the left as its potential energy will increase.


Option: 2

towards the right as its potential energy will decrease.


Option: 3

towards the left as its potential energy will decrease.

 


Option: 4

towards the right as its potential energy will increase.


Answers (1)

best_answer

F_{1}> F_{2}

                                                        F_{net}(towards right)

electric field intensity is more at +q as field lines are closer

V_{2}-V_{1}=-PE_{2}\cos \theta _{2}-\left ( -PE_{1}\cos \theta _{1} \right )

\theta _{1}=\theta _{2}=180^{o}(along givenline )

E_{2}< E_{1}(as it move towards right)

=\left ( +PE_{2} \right )-\left ( +PE_{1} \right )

\therefore \Delta U\Rightarrow Decrease

Posted by

chirag

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