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A half ring of radius R has a charge of $\lambda$ per unit length. The electric potential at the centre of the half ring is:
Option: 1
$\frac{k\lambda}{R}$

Option: 2
$k\pi \lambda$

Option: 3
$\frac{k\lambda}{\pi R}$

Option: 4
$\frac{k\pi R}{R}$

Answers (1)

Potential

$V = \frac{kq}{R} = k * \frac{\pi R * length}{R}$

$= \frac{k*\pi R \lambda}{R} = k\pi \lambda$

Posted by

Kshitij

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