Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

A half ring of radius R has a charge of $\lambda$ per unit length. The electric potential at the centre of the half ring is:
Option: 1
$\frac{k\lambda}{R}$

Option: 2
$k\pi \lambda$

Option: 3
$\frac{k\lambda}{\pi R}$

Option: 4
$\frac{k\pi R}{R}$

Answers (1)

Potential

$V = \frac{kq}{R} = k * \frac{\pi R * length}{R}$

$= \frac{k*\pi R \lambda}{R} = k\pi \lambda$

Posted by

Kshitij

View full answer

NEET 2024 Most scoring concepts

Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG Paper Leak 2026 LIVE: NTA response sheet soon at neet.nta.nic.in; RSOG investigation on paper leak

anam-khan

NEET UG 2026 irregularities under investigation; NTA says full cooperation being extended to agencies

anam-khan

NEET UG 2026 Tie-Breaking Rule Explained: Here’s how ranks are decided

Latest Question