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A heater coil is cut into two equal parts and only one part is now used in the heater.

Option: 1

2 times


Option: 2

4 times


Option: 3

\frac{1}{4} times


Option: 4

\frac{1}{2} times


Answers (1)

best_answer

\begin{aligned} \rightarrow \quad H=\frac{v^2 \Delta z}{R} \\ \end{aligned}                                              ........(i)

and   \begin{aligned} H^{\prime}=\frac{V^2 \Delta t}{R^{\prime}}, R^{\prime}=R / 2 \\ \end{aligned}

                \begin{aligned} =\frac{v^2 \cdot \Delta t}{R / 2}=\frac{2 v^2-\Delta t}{R} \text { AD } \\ \end{aligned}        .......(ii)

    From (i) and (ii)

                 \begin{aligned} & H=\frac{H^{\prime}}{2} \\ \end{aligned}

     \begin{aligned} \Rightarrow \quad H^{\prime}=2 H \end{aligned}

 

Posted by

himanshu.meshram

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