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A magnet is parallel to a uniform magnetic field. If it is rotated by 60°, the work done is 0.8 J. How much work is done in moving it 30° further?
Option: 1
$0.8 \times 10^7 \mathrm{erg}$

Option: 2
$0.4 \mathrm{~J}$

Option: 3
$8 \mathrm{~J}$

Option: 4
$0.8 \mathrm{~erg}$

Answers (1)

best_answer

$\cos 60^{\circ}=\frac{1}{2}, \cos 90^{\circ}=1 \\$

$\cos 90^{\circ}-\cos 60^{\circ}=\frac{1}{2}, 0.8 \mathrm{Jmore}$

Posted by

Gaurav

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