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  • A man of 120 pounds was made to stand against the inner wall of a hollow cylinder and the rotor of radius 10m is rotating at its vertical axis with a speed of <img alt="2rads-1" src=

A man of 120 pounds was made to stand against the inner wall of a hollow cylinder and the rotor of radius 10m is rotating at its vertical axis with a speed of 2rads-1, so what will the coefficient of friction between the wall and his clothing be?

Option: 1

0.25


Option: 2

0.35


Option: 3

0.45


Option: 4

0.15


Answers (1)

best_answer

As we know to calculate the minimum angular speed of the rotation \omega=\sqrt{\frac{g}{\mu R}}

\omega=2rad^{-1}

g=9.8m/s^2

R = 10m

μ = ?

\mu\ =\ \ g/\omega^2R

\mu=9.8/\left(2\right)^210

\mu=\frac{9.8}{40}

μ=0.25

 

 

 

Posted by

Anam Khan

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