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  • A metal M exists in the fourth period of periodic table. It can achieve many oxidation states, still forms with fluorides

A metal M exists in the fourth period of periodic table. It can achieve many oxidation states, still forms \mathrm{MF_{4}} with fluorides and does not form \mathrm{MF_{7}}. The highest oxidation state is achieved by anionic oxides \mathrm{MO_{4}^{-}} which are intensely purple-coloured. It is found as \mathrm{MO_{2}} in nature. What is M?

Option: 1

Co


Option: 2

Mn


Option: 3

Cr


Option: 4

V


Answers (1)

best_answer

Manganese forms \mathrm{MnO}_4^{-}which is purple coloured. It resides in 4^{\text {th }} period and has multiple oxidation states. But it cannot form MnF7 because of steric congestion. So, It achieves its highest oxidation state by reacting with oxygen to form permanganate anion.

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jitender.kumar

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