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A mono-chromatic point source S radiating wavelength\mathrm{6000 \AA} with power 2 \mathrm{w}_1 an aperture A of diameter 0.1 metre and a large screen Sc are placed as shown in figure. A photo emission detector D of surface Area 0.5 \mathrm{~cm}^2 is placed at the centre of the screen. The efficiency of the detector for the photo-electro generation per incident photon is 0.9

Question:

Light from a discharge tube containing hydrogen atoms falls on the surface of a piece of sodium. The kinetic energy of the fastest photo-electrons emitted from sodium is 0.73 eV. The work function for sodium is 1.82 eV. Then the energy of the photons causing photoelectric emission is:

Option: 1

1.55 eV


Option: 2

1.95 eV


Option: 3

2.05 eV


Option: 4

2.55 eV


Answers (1)

best_answer

According to Einstein’s photo-electric equation, the maximum kinetic energy EK of the emitted electrons is given by

\mathrm{E_{\mathrm{K}}^{\max }=h v-W}

where \mathrm{\text { hv }} is the energy of photons causing the photo- electric emission and W is the work-function of the emitting surface.

\mathrm{\text { Given that, } E_{\mathrm{K}}^{\max }=0.73 \mathrm{eV} \text { and } \mathrm{W}=1.82 \mathrm{eV}}

\mathrm{\therefore \mathrm{hv}=\mathrm{E}_{\mathrm{K}}^{\max }+\mathrm{W}=0.73 \mathrm{eV}+1.82 \mathrm{eV}=2.55 \mathrm{eV}}

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