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A non-planar loop of conducting wire carrying a current is placed as in diagram. Each of the straight section of the loop of length (a). The magnetic field due to this wop ad the point \left(\frac{a}{2}, 0, \frac{a}{2}\right) is

Option: 1

\frac{a}{\sqrt{2}}(\hat{i}+\hat{\jmath})


Option: 2

\frac{a}{\sqrt{2}}(\hat{r}+\hat{k})


Option: 3

\frac{a}{\sqrt{2}}(\vec{k}+\hat{j})


Option: 4

None


Answers (1)

best_answer

The magnetic field due to complete loop =(B-field due to planar loop in the y - z planer) + (B-field due to planar loop in the x-y plane)

=(\hat{i}+\hat{k}) \cdot a \cos 45 \\

=\left(\frac{a}{\sqrt{2}} \hat{i}+\frac{a}{\sqrt{2}} \hat{j}\right)

Posted by

chirag

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