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  • A nucleus with mass number 220 initially at rest emits a particle. If the value of the reaction is <img alt="\mathrm{7.50 \, \mathrm{Me

A nucleus with mass number 220 initially at rest emits a particle. If the \mathrm{Q} value of the reaction is \mathrm{7.50 \, \mathrm{MeV}} and only one photon of energy \mathrm{1.50\, \mathrm{MeV}} is subsequently emitted after the emission of the \mathrm{\alpha -} particle, the kinetic energy of the \mathrm{\alpha -} particle is

Option: 1

5.40\, \mathrm{Mev}


Option: 2

5.60\, \mathrm{Mev}


Option: 3

5.80\, \mathrm{Mev}


Option: 4

5.90\, \mathrm{Mev}


Answers (1)

best_answer

Kinetic energy of \alpha particle is given by

\mathrm{K_\alpha=\frac{(Q-\Delta E) Y}{Y+4}=\frac{(7.50-1.50) \times 216}{216+4}}

\mathrm{K_\alpha=\frac{6 \times 216}{220}=5.89 \, \mathrm{MeV}}

correct option is (d).

Posted by

Deependra Verma

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