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A parallel plate capacitor has a uniform electric field E in the space between the plates. If the distance between the plates is d and area of each plate is A, the energy stored in the capacitor is:

Option: 1

\frac{1}{2}\varepsilon _{0}E^{2}


Option: 2

E^{2} Ad/\varepsilon _{0}


Option: 3

\frac{1}{2}\varepsilon _{0}E^{2}Ad


Option: 4

\varepsilon _{0}E^{2}Ad


Answers (1)

best_answer

 

Parallel Plate Capacitor -

C=frac{epsilon _{0}A}{d}

- wherein

Area - A separation between two plates.

 

 

Parallel Plate Capacitor -

C=frac{epsilon _{0}A}{d}

- wherein

Area - A separation between two plates.

 

C= \frac{\varepsilon _{0}A}{d}

V = E.d

Energy stored in the capacitor = \frac{1}{2}CV^{2}

= \frac{1}{2}\frac{\varepsilon _{0}}{d}.\left ( E.d \right )^{2}=\frac{1}{2}\varepsilon _{0}AdE^{2}

Posted by

Pankaj Sanodiya

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