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A particle having charge q moves with a velocity \overrightarrow{\mathrm{v}}  through a region in which both an electric field \overrightarrow{\mathrm{E}} and a magnetic field \overrightarrow{\mathrm{B}}  are present. The force on the particle is

Option: 1

\mathrm{q \overrightarrow{\mathrm{E}}+q(\overrightarrow{\mathrm{B}} \times\overrightarrow{\mathrm{v}})}


Option: 2

\mathrm{q }\overrightarrow{\mathrm{E}} \cdot(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{v}})


Option: 3

\mathrm{q }\overrightarrow{\mathrm{v}}+\mathrm{q}(\overrightarrow{\mathrm{E}} \times \overrightarrow{\mathrm{B}})


Option: 4

\mathrm{q} \overrightarrow{\mathrm{E}}+\mathrm{q}(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})


Answers (1)

best_answer

Force due to electric field =\mathrm{qE}  Force due to magnetic field \mathrm{=q(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})} Net force experienced \mathrm{=q \overrightarrow{\mathrm{E}}+q(\overrightarrow{\mathrm{v}} \times \overrightarrow{\mathrm{B}})}

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chirag

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