Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A particle is ejected at a speed of 10  at an angle of 37 degrees from the horizontal. The radius of curvature at the time of projection is:Option

A particle is ejected at a speed of 10  at an angle of 37 degrees from the horizontal. The radius of curvature at the time of projection is:

Option: 1

12.78\ m


Option: 2

20.15\ m


Option: 3

50.6\ m


Option: 4

25\ m


Answers (1)

best_answer

Answer: (A) 12.78\ m

Explanation:

Radius of Curvature =  \frac{\left(\left\{1+\frac{dx}{dy}\right\}^2\right)^\frac{3}{2}}{\frac{d^2y}{dx^2}}

Equation for projectile is given as:

y=xtan\theta\ -\frac{1}{2}\frac{gx^2}{u^2\cos^2\theta}    

Therefore, the first and second derivatives are:

\frac{dx}{dy}=\ tan\theta\ -\ \frac{gx}{u^2\cos^2\theta}

And,

\frac{d^2y}{dx^2}=-\frac{g}{u^2\cos^2\theta}                     

Now,


\frac{\left(1+\tan^2\theta\right)^\frac{3}{2}\times u^2\times\cos^2\theta}{g}

Or,  \frac{u^2}{gcos\theta}              

 

Or,   \frac{10\times 10}{9.8\times \cos37}=\ 12.78              
 

Posted by

avinash.dongre

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

MCC NEET UG counselling 2025 registration from July 21 for MBBS, BDS, AYUSH admissions
anam-khan

From 589 to 41: NEET candidate misses cut-off over silly error, HC orders re-checking of OMR sheet
anam-khan

CENTAC Puducherry’s NEET counselling rules ‘discriminatory’; Doctors with Disabilities demand revision

Latest Question