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A particle is executing simple harmonic motion with a time period T. At time t=0, it is at its position of equilibrium. The kinetic energy-time graph of the particle will look like:

 

Option: 1


Option: 2


Option: 3


Option: 4

None of the above


Answers (1)

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KE = \frac{1}{2} m \omega^{2} A^{2} \cos^{2} \omega t = (KE)_{max} \cos^{2} \omega t

t 0 T/4 T/2
KE KEmax 0 KEmin

 

Posted by

Shailly goel

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