Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A particle is thrown with 10m/s at an angle of  with horizontal the time at which its velo

A particle is thrown with 10m/s at an angle to 60^{\circ} with horizontal. The time at which its velocity is perpendicular to the initial velocity is ( g = 10 m/s )

Answers (1)

best_answer

Given- 

  • Initial velocity, u = 10 m/s
  • Angle of projection, θ = 60°
  • Gravitational acceleration, g = 10 m/s2

Condition for Perpendicularity - The velocity is perpendicular to the initial velocity when the dot product of the initial velocity vector and the velocity vector at time t is zero (u⋅v=0) $$
u_x v_x +u_y v_y=0
$$

  1. In x- axis, ux = vx = ucosθ = 10 x 0.5= 5 m/s
  2. In y- axis, uy = usinθ = 10 x sin 60= 8.66 m/s and vy = uy −gt = 8.66- 10t

$$
u_x v_x +u_y v_y=0 → 5×5+8.66×(8.66−10t)=0
$$ Simplyfing the equation, we get t = 1.15 seconds

Therefore, the time at which the velocity is perpendicular to the initial velocity is approximately 1.15 seconds.

Posted by

Saniya Khatri

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

Want a career in medicine without NEET? Consider paramedical courses after Class 12
anam-khan

AFMC hikes MBBS seat leaving bond penalty, mandates 7 years of commission service
anam-khan

‘Patience and not backing down’: Kabir Paharia’s SC fight eases MBBS admissions for disabled candidates

Latest Question