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A particle of charge q and mass m starts moving from the origin under the action of an electric field $\mathrm{\overrightarrow{E}=E_0 \hat{j}}$ and magnetic field $\mathrm{\overrightarrow {B}=B_0 \hat{k}.}$ Its speed at a point (a, y, b) is 10 m / s. The value of y is:
Option: 1
$\mathrm{\frac{25 m}{q E_0}}$

Option: 2
$\frac{100 \mathrm{~m}}{\mathrm{qE}}$

Option: 3
$\frac{50 \mathrm{~m}}{\mathrm{q} \mathrm{E}_0}$

Option: 4
$\frac{14 \mathrm{~m}}{\mathrm{q} \mathrm{E}_0}$

Answers (1)

best_answer

$\mathrm{\frac{1}{2} m v^2=(q E) y}$

Posted by

Devendra Khairwa

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