Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A plank is placed on a solid cylinder which rolls

A plank is placed on a solid cylinder which rolls on a horizontal surface.The two are of equal mass.There is no slipping in any of the surfaces in contact.Find the ratio of kinetic energy of plank and cylinder.

Answers (2)

ratio=\frac{0.5m(2v)^2}{0.5mv^2+0.5\frac{mr^2v^2}{2r^2}}=8:3

 

Posted by

Safeer PP

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

 

Kinetic energy of plank: \frac{1}{2} (m)((2v)^2)

Kinetic energy of cylinder is \frac{1}{2} (m)((v)^2) +\frac{1}{2}IW^2

where W is angular velocity

So kinetic energy of cylinder is \frac{1}{2} (m)((v)^2) +\frac{1}{2}\frac{mR^2}{2}(\frac{V}{R})^2=\frac{3}{4}(mv^2)

   ratio=\frac{0.5m(2v)^2}{0.5mv^2+0.5\frac{mr^2v^2}{2r^2}}=8:3???????

Posted by

avinash.dongre

View full answer

Similar Questions

Trending Articles/News

anam-khan

Haryana NEET UG Counselling 2025: Special stray round registration begins; choice filling till December 25
anam-khan

NEET UG 2025: JKBOPEE to hold physical stray round counselling for vacant MBBS, BDS seats
anam-khan

SC regularises BDS degrees of students granted relaxation in NEET percentile in Rajasthan

Latest Question