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  • A point charge of    is placed at origin. The intensity of el

A point charge of  \mathrm{0.009 \mu c}  is placed at origin. The intensity of electric field due to this charge at point \mathrm{(\sqrt{2}, \sqrt{7}, 0)} is -

Option: 1

\mathrm{(3 \sqrt{2} \hat{i}+3 \sqrt{7} \hat{j}) \mathrm{N} / \mathrm{C} }


Option: 2

\mathrm{(2 \sqrt{3} \hat{i}+3 \sqrt{7} \hat{j}) \mathrm{N} / \mathrm{C} }


Option: 3

\mathrm{(3 \sqrt{2} \hat{i}+7 \sqrt{3} \hat{j}) N / C }


Option: 4

\mathrm{(\sqrt{2} \hat{i}+7 \sqrt{3} \hat{j}) N / C}


Answers (1)

best_answer

key points.-

 \mathrm{\vec{E}=\frac{k q}{\gamma^2} \hat{\gamma} }
\mathrm{\vec{E}=\frac{k q}{\gamma^3} \vec{\gamma} }
Now


\mathrm{\vec{\gamma}=x \hat{\imath}+y \hat{\jmath} }

Posted by

jitender.kumar

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