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A potential barrier of 0.5 V exists across a P–N junction. If the depletion region is $5 \times 10^{-7}m$ wide, then intensity of electric field in this region is
Option: 1
$10^{6}\; v/m$

Option: 2
$10^{8}\; v/m$

Option: 3
$10^{-5}\; v/m$

Option: 4
$10^{-6}\; v/m$

Answers (1)

best_answer

Answer (1)

Electric field $E=\frac{\Delta V}{\Delta x}$

$=\frac{0.5}{5 \times 10^{-7}}=10^{6}\; v/m$

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Nehul

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