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9) A potentiometer wire of length 1 m has a resistance of 5 ohm. It is connected to a 8 V battery in series with a resistance of 15 ohm. Determine the emf of primary cell which gives a balance point at 60 cm.

Answers (1)

Find the current through the wire I= 8/(20)=0.4A

voltage across potentiometer wire = 5*0.4=2Volt

60/100=V'/2

V'=1.2V

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Safeer PP

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