9) A potentiometer wire of length 1 m has a resistance of 5 ohm. It is connected to a 8 V battery in series with a resistance of 15 ohm. Determine the emf of primary cell which gives a balance point at 60 cm.
Find the current through the wire I= 8/(20)=0.4A
voltage across potentiometer wire = 5*0.4=2Volt
60/100=V'/2
V'=1.2V