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A proton is fired from origin with velocity \mathrm{\vec{v}=v_0 \hat{j}+v_0 \hat{k}}  in a uniform magnetic field  \mathrm{\vec{B}=-B_0 \hat{j}} . IN the subsequent motion of the proton:

Option: 1

its z co-ordinate can never be negative


Option: 2

its x co-ordinate can never be positive
 


Option: 3

its x and z co-ordinates cannot be zero at the same time
 


Option: 4

its y co-ordinate will be proportional to its time of flight


Answers (1)

best_answer

Fy =0 hence v y= constant
\mathrm{y} \times \mathrm{t}
Trajectory of proton will be as shown in diagram.

Posted by

Sanket Gandhi

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