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A pulse of light of duration 10^{-6} \mathrm{~S} is absorbed completely by a small object initially at rest. If the power of the pulse is \mathrm{60 \times 10^{-3} \mathrm{~W}}, calculate the final momentum of the object.

Option: 1

10 \times 10^{-17} \mathrm{~kg} \mathrm{~m} \mathrm{~s}^{-1} \\


Option: 2

20 \times 10^{-17} \mathrm{~kg} \mathrm{~m} \mathrm{~s}^{-1} \\


Option: 3

30 \times 10^{-17} \mathrm{~kg} \mathrm{~m} \mathrm{~s}^{-1} \\


Option: 4

40 \times 10^{-17} \mathrm{~kg} \mathrm{~m} \mathrm{~s}^{-1}


Answers (1)

best_answer

Given data :

\\\mathrm{t}=10^{-6} \mathrm{~s}\\ \\\text{power} =60 \times 10^{-3} \mathrm{~W}\\ \\\text{final momentum p} = ?

\begin{aligned} \text{P} & \: \: \: =\mathrm{\frac{U}{C}=\frac{\text { power } \times t}{C}} \\ & \: \: \: = \mathrm{\frac{60 \times 10^{-3} \times 10^{-6}}{3 \times 10^8}} \\ & \mathrm{P=20 \times 10^{-17} \mathrm{kgms}^{-1}} \end{aligned}

Answer : 20 \times 10^{-17} \mathrm{~kg} \mathrm{~m} \mathrm{~s}^{-1}

 

Posted by

Rakesh

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