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A radioactive nucleus emits 4 \alpha  particles and 7 \beta  particles in succession. The ratio of number of neutrons to that of protons is -

Option: 1

\mathrm{\frac{A-Z-11}{Z-2} }


Option: 2

\mathrm{\frac{A-Z-13}{z-1} }


Option: 3

\mathrm{\frac{A-Z-13}{Z-2} }


Option: 4

\mathrm{\frac{A-Z-15}{Z-1}}


Answers (1)

best_answer

No. of neutrons = Atomic mass number - Atomic number 
No. of protons = Atomic number

A \stackrel{4 \alpha}{\longrightarrow} A-16 \stackrel{7 \beta}{\longrightarrow} A-16 \rightarrow \begin{gathered} \text { new atomic mass number } \end{gathered}

2 \stackrel{4 \alpha}{\longrightarrow} z-8 \stackrel{2 \beta}{\longrightarrow}(2-1)\text{ new atomic number }

\text{No. of proton =z-1 }
\begin{aligned} \text { No of neutron } & =\mathrm{A-16-(2-1) }\\ & \mathrm{=A-2-15 }\\ & \mathrm{\left[\frac{n}{\rho}\right]=\frac{A-z-15}{z-1}}\end{aligned}

 

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Rakesh

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