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  • A radioactive nucleus undergoes spontaneous decay in the sequence <img alt="_{Z}^{A}X\rightarrow Z-1B\rightarrow Z-3\rightarrow C\rig

A radioactive nucleus _{Z}^{A}X undergoes spontaneous decay in the sequence _{Z}^{A}X\rightarrow Z-1B\rightarrow Z-3\rightarrow C\rightarrow Z-2D,where Z is the atomic number of element X.The possible decay particles in the sequence are

Option: 1

\alpha ,\beta ^{-},\beta ^{+}


Option: 2

\alpha ,\beta ^{+},\beta ^{-}


Option: 3

\beta ^{+},\alpha,\beta ^{-}


Option: 4

\beta ^{-},\alpha,\beta ^{+}


Answers (1)

best_answer

_{Z}^{A}X\rightarrow \: \: \: \: \: B\rightarrow \: \: \: \: C\rightarrow\: \: \: D

             Z-1        Z-3     Z-2

With \beta ^{+} decay ,Z decrease by 1 with \alpha-decay,Z decrease by 2(from z-1 to z-3)

with \beta ^{-} decay , Z increase by 1(from z-3 to z-2)

decay particles in the sequence are \beta ^{+},\alpha,\beta ^{-}

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Rishi

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