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  • A radioactive sample at any instant has its disintegration rate 5000 disintegrations per minute. After 5 minutes, the rate is 1250 disintegrations per minute. Then, the decay constant (per minute)

A radioactive sample at any instant has its disintegration rate 5000 disintegrations per minute. After 5 minutes, the rate is 1250 disintegrations per minute. Then, the decay constant (per minute) is

Option: 1

 0.4 \ln 2


Option: 2

 0.4 \ln 3


Option: 3

0.8 \ln 2


Option: 4

 0.4 \ln 5


Answers (1)

best_answer

\lambda=\frac{0.693 \log _{10} \frac{N_0}{N}}{t \log _{10} 2}

\text { or } \lambda=\frac{0.693 \times \log _{10}\left(\frac{5000}{1250}\right)}{5 \times \log _{10} 2}

\text { or } \lambda=\frac{2 \ln 2}{5}=0.4 \ln 2

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jitender.kumar

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