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A reaction \mathrm{P \longrightarrow Q} follows the first order Kinetics, choose the correct option.

(A) The degree of dissociation is equal to \mathrm{\left(1-e^{-K t}\right)}.
(B) A plot of reciprocal concentration of the reactant Vs time gives a straight line.
(c) Time taken for the completion of 75 % reaction is thrice the \mathrm{t_{1 / 2}} of reaction
(D) The pre-exponential factor in the Arrherices Equation has the dimension of Time (T).

Option: 1

The degree of dissociation is equal to \mathrm{\left(1-e^{-K t}\right)}.


Option: 2

A plot of reciprocal concentration of the reactant Vs time gives a straight line.


Option: 3

Time taken for the completion of 75 % reaction is thrice the \mathrm{t_{1 / 2}} of reaction


Option: 4

The pre-exponential factor in the Arrherices Equation has the dimension of Time (T).


Answers (1)

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For a first order reaction \mathrm{P\rightarrow Q}, we have 

\mathrm{\ln \frac{P_t}{P_0}=-k t \text { or } [P]_{t}=[P]_0 \; e^{-k t}}

in terms of degree of dissociation, 

\mathrm{[P]_{t}=[A]_{o}(1-\alpha)}

Hence, \mathrm{[P]_0(1-\alpha)= [P]_0 \; e^{-k t}}

\mathrm{\alpha=\left(1-e^{-k t}\right)}

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shivangi.shekhar

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