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A rigid close container contains an ideal gas at \small 27^{\circ}C temperature and 2 atm pressure, if temperature raised to \small 127^{\circ}C then find the final pressure (in atm) of the gas.

Option: 1

2.24


Option: 2

1.46


Option: 3

2.66


Option: 4

1.86


Answers (1)

best_answer

We know from Gay Lussac’s Law that the Pressure-Temperature relationship can be written as follows:

\frac{P_1}{T_1}=\frac{P_2}{T_2}

Now,

\\P_1=2atm\\T_1=27+273=300K\\T_2=127 + 273=400K\\\\P_2=?\\\frac{2}{P_2}=\frac{300}{400}\\P_2=\frac{800}{300}=2.66atm

Option (3) is correct

Posted by

Shailly goel

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