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  • A sample of a hydrate of barium chloride weighing 61 g was heated until all the water of hydration is removed. The dried sample weighed 52 g. The formula of the hydrated salt is : (atomic mass, Ba=

A sample of a hydrate of barium chloride weighing 61 g was heated until all the water of hydration is removed. The dried sample weighed 52 g. The formula of the hydrated salt is : (atomic mass, Ba=137 amu, Cl=35.5 amu)

Option: 1

BaCl2.H2O


Option: 2

BaCl2.2H2O


Option: 3

BaCl2.3H2O


Option: 4

BaCl2.4H2O


Answers (1)

best_answer

Given

The dried sample of BaCl2 is 52g.

Thus moles of BaCl2 = 52/208
                               = 0.25 moles

Now, the weight of hydrated barium chloride = 61g

Thus, the weight of water in the sample = 61 - 52
                                                     = 9g

Thus moles of water = 9 / 18
                              = 0.5 moles

We know in 52g of BaCl2       9g gram of water is present

Now, in 0.25 mole of BaCl2    0.5 mole of water is present 

let's write chemical formula-

0.25BaCl2.0.5H2O

in simple form

1/4BaCl2.1/2H2O

it can written as BaCl2.4/2H2O  ==   BaCl2.2H2O

Thus, the formula of the compound is BaCl2.2H2O

Therefore, Option(2) is correct

Posted by

Pankaj Sanodiya

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