A segment of DNA has 120 adenine and 120 cytosine bases. The total number of nucleotides present in the segment is
60
120
240
480
As we have already studied in Chargaff’s Rule -
A = 120, so T will also be 120; C = 120, so G will also be 120
Hence, the total number of nucleotides will be 120 X 4 = 480
Hence, the correct option is (d).