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  • A silicon specimen is made into a -type semiconductor by doping, on an average, one indium atom per <img alt="5\times10^{7}" src="https://entrancecorner.oncodecogs.com/gif.latex?5%5Ctimes10%5E%7B7%

A silicon specimen is made into a -type semiconductor by doping, on an average, one indium atom per 5\times10^{7} silicon atoms. If the number density of atoms in the silicon specimen is 5\times10^{28} atoms \mathrm{m^{-3}}, then the number of acceptor atoms in silicon per cubic centimeter will be

Option: 1

2.5 \times 10^{30} \text{atom}\, \mathrm{cm}^{-3}
 


Option: 2

\mathrm{2.5 \times 10^{35}\text{ atom }cm^{-3}}
 


Option: 3

\mathrm{1 \times 10^{13} \text{atom cm} { }^{-3}}
 


Option: 4

\mathrm{1 \times 10^{15} \text{atom}\: \mathrm{cm}^{-3}}


Answers (1)

best_answer

Number density of atoms in silicon specimen

\mathrm{ =5 \times 10^{28} \text { atoms }-\mathrm{m}^{-3}=5 \times 10^{22} \text { atoms } \mathrm{cm}^{-3} . }

Since, 1 atom of indium is doped in \mathrm{ 5 \times 10^7 } silicon atoms, so total number of indium atoms doped per \mathrm{ \mathrm{cm}^3 } of silicon will be

\mathrm{ n=\frac{5 \times 10^{22}}{5 \times 10^7}=10^{15} \text { atom- } \mathrm{cm}^{-3} \text {. } }

Hence option 4 is correct.
 

Posted by

Sanket Gandhi

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