Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  •   A sinusoidal voltage V(t) = 100 sin (500t) is applied across a pure inductance of  L = 0.02 H. The current through the coil  is :        </p

  A sinusoidal voltage V(t) = 100 sin (500t) is applied across a pure inductance of  L = 0.02 H. The current through the coil  is :      

 

Option: 1

10\cos (500t)


Option: 2

-10\cos (500t)


Option: 3

10\sin (500t)


Option: 4

-10\sin (500t)


Answers (1)

\\ \text{We know that voltage across inductor} \\ \mathrm{V}=\mathrm{L} \frac{\mathrm{di}}{\mathrm{dt}} \\ \mathrm{i}=\frac{1}{\mathrm{~L}} \int 100 \sin (500 \mathrm{t}) \mathrm{dt} \mathrm{i}=-10 \cos 500 t

Posted by

Kshitij

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET 2025 Biology Weightage: Chapter-wise breakdown for Class 11, 12, important topics
anam-khan

Bihar NEET PG 2024 stray vacancy round registration starts tomorrow; schedule out
anam-khan

NEET UG must for foreign MBBS graduates to obtain eligibility certificate; NMC regulations explained

Latest Question