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  •   A sinusoidal voltage V(t) = 100 sin (500t) is applied across a pure inductance of  L = 0.02 H. The current through the coil  is :        </p

  A sinusoidal voltage V(t) = 100 sin (500t) is applied across a pure inductance of  L = 0.02 H. The current through the coil  is :      

 

Option: 1

10\cos (500t)


Option: 2

-10\cos (500t)


Option: 3

10\sin (500t)


Option: 4

-10\sin (500t)


Answers (1)

\\ \text{We know that voltage across inductor} \\ \mathrm{V}=\mathrm{L} \frac{\mathrm{di}}{\mathrm{dt}} \\ \mathrm{i}=\frac{1}{\mathrm{~L}} \int 100 \sin (500 \mathrm{t}) \mathrm{dt} \mathrm{i}=-10 \cos 500 t

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Kshitij

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