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  • A source of light is placed at a distance of form a photo cell and cut off potential is found to be <img alt="V_{0}" src="h

A source of light is placed at a distance of 1m form a photo cell and cut off potential is found to be V_{0} . If the distance is doubled, the cut off potential will be-

Option: 1

2V_{0}


Option: 2

\frac{V_{0}}{2}


Option: 3

V_{0}


Option: 4

\frac{V_{0}}{4}


Answers (1)

best_answer

When distance is increased, the intensity is reduced. But intensity has no effect on cut-off potential.

Posted by

Irshad Anwar

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