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  • A square loop, carrying a steady current I, is placed in a horizontal plane near a long straight conductor carrying a steady current I1 at a distance d from the conductor as shown in fig

A square loop, carrying a steady current I, is placed in a horizontal plane near a long straight conductor carrying a steady current I1 at a distance d from the conductor as shown in figure. The loop will experience

Option: 1

A net torque acting downward normal to the horizontal plane


Option: 2

A net attractive force towards the conductor


Option: 3

A net repulsive force away from the conductor


Option: 4

A net torque acting upward perpendicular to the horizontal plane


Answers (1)

best_answer

\vec{F}_{2}=-\vec{F}_{4}$ \\ $\vec{F}_{1}=\frac{\mu_{0} I_{1} I_{2} \ell}{2 \pi d}$ \\ $\vec{F}_{3}=\frac{\mu_{0} I_{1} I_{2} \ell}{2 \pi(d+\ell)}$ \\ $\vec{F}_{1}>F_{3}$ \\ So wire attract loop.

So, a net attractive force towards the conductor

Posted by

Devendra Khairwa

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