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A substance shows a Ramon line at 4567~ \AA when exciting line 4358 ~ \AA is used. The position of stokes an antistoke line for the same substance when the exciting line 4047~ \AA used.
 

Option: 1

3882 ~\AA


Option: 2

4000 ~\AA


Option: 3

2400~ \AA


Option: 4

2404 ~\AA


Answers (1)

best_answer

\mathrm{\bar{u}_0=22946 \mathrm{~cm}^{-1}, \bar{u}_R=21896 \mathrm{~cm}^{-1}}

Roman stiff:- \mathrm{ \Delta \bar{u}=\bar{u}_0-\bar{u}_R=1050 \mathrm{~cm}^{-1}}
\mathrm{ \Delta \bar{u}} does not depends upon the incident frequent

\mathrm{ \bar{u}_0=\frac{1}{4047 \times 10^{-5} \mathrm{~cm}}=24710 \mathrm{~cm}^{-1}}

Thus, the wave number of stoke \& anti-stokes lines are-

\begin{aligned}
=\mathrm{\overline{u_0} \pm \Delta V} & =\mathrm{(24710 \pm 1050)} \mathrm{cm}^{-1} \\
& =23660 \mathrm{~cm}^{-1} \text { and } 25760 \mathrm{~cm}^{-1} \\
\text { or } \lambda_{\text {stoke }} & =4226 \AA \\
\lambda_{\text {antistoke }} & =3882 \AA 
\end{aligned}

Posted by

Divya Prakash Singh

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