Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A tangential force acts at the top of a thin spherical shell of mass <img alt="\mathrm{m}" src="https

A tangential force \mathrm{F} acts at the top of a thin spherical shell of mass \mathrm{m} and radius \mathrm{R}. The acceleration of the shell if it rolls without slipping -
 

Option: 1

\mathrm{\frac{6 F}{5 m}}
 


Option: 2

\mathrm{\frac{6 m}{5 f}}
 


Option: 3

\mathrm{\frac{5 f}{6 m}}
 


Option: 4

\mathrm{\frac{3 f}{4 m}}


Answers (1)

best_answer

If \mathrm{a} is the acceleration of \mathrm{CM}, then

\mathrm{F+f =m a }

\mathrm{F R-f R =I \alpha}..........(1)

For pure rolling \mathrm{\alpha=\frac{a}{R} \: and \: I=\frac{2}{3} m R^2}

put the value of \alpha in equation \mathrm{C} -

\mathrm{F R-f R =I \times \alpha=\frac{2}{3} m R^2 \times \frac{a}{R} }

\mathrm{F R-f R =\frac{2}{3} m R a }

\mathrm{a =\frac{6 F}{5 m} }

Hence option 1 is correct.

 

Posted by

chirag

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET 2026 LIVE: NTA to close application correction window tomorrow; admit card, exam dates, pattern
anam-khan

NEET 2026 registration deadline extended to March 11 for MBBS, BDS; exam on May 3
anam-khan

NEET 2026 Registration LIVE: NTA extends MBBS, BDS application deadline to March 11; how to apply

Latest Question