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A thick current carrying cable of radius 'R' carries current $'I'$ uniformly distributed across its cross-section. The variation of magnetic field B(r) due to the cable with the distance $'r'$ from the axis of the cable is represented by:
Option: 1

Option: 2

Option: 3

Option: 4

Answers (1)

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$B=\frac{\mu _{o}Ir}{2\pi R^{2}}\left ( r< R \right )$

$B=\frac{\mu _{o}I}{2\pi r}\left ( r> R \right )$

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rishi.raj

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