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 A time varying current I (t)= 2 \cos wt  is flowing in primary coil of 200 turns with frequency 40 Hz . The coefficient of mutual induction is 10 m H . 

Find the emf induced (max) (in mV) is secondary coil of 400 turns 

Option: 1

50.24


Option: 2

12.56


Option: 3

50.24


Option: 4

12.56


Answers (1)

best_answer

As we have learned

According to Faraday's Second Law -

\varepsilon _{2}= -N_{2}\frac{d\phi_{2}}{dt}= -M\frac{dI_{1}}{dt}

-

 

 induced emf , \varepsilon = \frac{-\mu dI_1}{dt}

\varepsilon = \frac{-\mu d}{dt}(2\cos wt )

\varepsilon = \mu 2w \sin wt

For Max emf |\sin wt|= 1

\varepsilon _{max} = 2 Mw

 \varepsilon _{max} = 2 M\times 2 \pi f

\varepsilon _{max} = 2 \times 10 \times 10^{-3}\times 2\times 3.14\times 40

 \varepsilon _{max} = 50.24 mV

Posted by

vishal kumar

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