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  • A transistor is connected in a common emitter configuration. The collector supply is  a

A transistor is connected in a common emitter configuration. The collector supply is 8 \mathrm{~V} and the voltage drop across a resistor of 800 \Omegain the collector circuit is 0.5 \mathrm{~V}If the current gain factor is 0.96 then the base current is

Option: 1

15 \mu \mathrm{A}


Option: 2

20 \mu \mathrm{A}


Option: 3

24 \mu \mathrm{A}


Option: 4

26 \mu \mathrm{A}


Answers (1)

best_answer

\beta=\frac{\alpha}{1-\alpha}=\frac{0.96}{1-0.96}=24
The collector current is
I_c=\text { voltage drop across collector resistor} / resistance
=\frac{0.5}{800} \mathrm{~A}=0.625 \times 10^{-3} \mathrm{~A}
From the definition of
\begin{aligned} \beta & =\frac{i_c}{i_b}= \\ \Rightarrow i_b & =\frac{i_c}{\beta}=\frac{0.625 \times 10^3}{24} \mathrm{~A}=26 \mathrm{\mu A} \end{aligned}
 

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Rakesh

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