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A uniform chain of length 2m is held on a smooth horizontal table so that half of it hangs over the edge. If it is released from rest, the velocity (in m/sec) with which it leaves the table will be nearest to 

Option: 1 2

Option: 2 4

Option: 3 6

Option: 4 8

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v = \sqrt{gL\left [ 1 - \frac{1}{n^{2}} \right ]} = \sqrt{10 \times 2 \left [ 1- \frac{1}{2^{2}} \right ]} = \sqrt{15} = 3.87 m/s \approx 4 m/s

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avinash.dongre

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