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  • A vibration magnetometer placed in magnetic meridian has a small bar magnet, the magnet executes oscillations with a time period of 2 sec in earth's horizontal magnetic field of 24 microtesla.

A vibration magnetometer placed in magnetic meridian has a small bar magnet, the magnet executes oscillations with a time period of 2 sec in earth's horizontal magnetic field of 24 microtesla. When a horizontal field of 18 microtesla is produced opposite to the earth's field by placing a current carrying wire, the new time period of magnet will be

Option: 1

4 s


Option: 2

1 s


Option: 3

2 s


Option: 4

3 s


Answers (1)

best_answer

\begin{aligned} &\mathrm{T}=2 \pi \sqrt{\frac{\mathrm{I}}{\mathrm{MB}}} \mathrm{T} \alpha \frac{1}{\sqrt{\mathrm{B}}}\\ &\frac{\mathrm{T}_1}{\mathrm{~T}_2}=\sqrt{\frac{\mathrm{B}_2}{\mathrm{~B}_1}}\\ &\frac{T_1}{2}=\sqrt{\frac{24}{24-18}}=\sqrt{\frac{24}{6}}=2\\ &\mathrm{T}_1=4 \end{aligned}

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Rishabh

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