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  • A vibration magnetometer placed in magnetic meridian has a small bar magnet. The magnet executes oscillations with a time period of 2 sec in earth's horizontal magnetic field of 24 microtesla.

A vibration magnetometer placed in magnetic meridian has a small bar magnet. The magnet executes oscillations with a time period of 2 sec in earth's horizontal magnetic field of 24 microtesla. When a horizontal field of 18 microtesla is produced opposite to the earth's field by placing a current carrying wire, the new time period of magnet will be

Option: 1

1 s


Option: 2

2 s


Option: 3

3 s


Option: 4

4 s


Answers (1)

best_answer

Time period of a vibration magnetometer,

\mathrm{T} \propto \frac{1}{\sqrt{\mathrm{B}}} \Rightarrow \frac{\mathrm{T}_1}{\mathrm{~T}_2}=\sqrt{\frac{\mathrm{B}_2}{\mathrm{~B}_1}} \\

\Rightarrow \mathrm{T}_2=\mathrm{T}_1 \sqrt{\frac{\mathrm{B}_1}{\mathrm{~B}_2}}=2 \sqrt{\frac{24 \times 10^{-6}}{6 \times 10^{-6}}=4 \mathrm{~s}}

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Riya

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