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  • . A voltmeter having a resistance of 1800 is employed to meaure the potential difference across 200 <img alt="\Om

. A voltmeter having a resistance of 1800 \Omega is employed to meaure the potential difference across 200 \Omega resistance which is connected to be power supply of 50 V and internal resistance 20 \Omega. What is the approximate percentage change in the p.d. across 200 \Omega resistance as a result of connecting the voltmeter across it?

Option: 1

2.2%


Option: 2

5%


Option: 3

10%


Option: 4

20%


Answers (1)

\begin{aligned} &\mathrm{ V_1=E-i r=50-\frac{50}{220} \times 20 }\\ &\mathrm{ =50-4.6=45.4 \mathrm{~V} }\\ &\mathrm{ \text { Now, } V_2=50-\frac{50}{180} \times 20=44.4 \mathrm{~V}}\\ &\mathrm{\text { Percentage change }=\frac{V_1-V_2}{V_1} \times 100=2.27 \text { (also see the question) }}\\ \end{aligned}

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Kshitij

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