Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Medical
  • A wire carrying a current along the positive x-axis has length <img alt="\mathrm{L}" src="https://ent

A wire carrying a current \mathrm{I} along the positive x-axis has length \mathrm{L}. It is kept in a magnetic field \mathrm{\vec{B}=(2 \hat{i}+3 \hat{j}-4 \hat{k}) T}. The magnitude of the magnetic force acting on the wire is:

Option: 1

3 \, \, \mathrm{IL}


Option: 2

\sqrt{5} \, \, \mathrm{IL}


Option: 3

5\, \, \mathrm{IL}


Option: 4

\sqrt{3} \, \, IL


Answers (1)

best_answer

\begin{aligned} & \vec{F}=I(\vec{L} \times \vec{B}) \\ & =I[(L \hat{i}) \times(2 \hat{i}+3 \hat{j}-4 \hat{k})] \\ & \vec{F}=I L(3 \hat{k}+4 \hat{j}) \\ & |\vec{F}|=5 I L \end{aligned}

Posted by

manish painkra

View full answer

NEET 2024 Most scoring concepts

    Just Study 32% of the NEET syllabus and Score up to 100% marks

Similar Questions

Trending Articles/News

anam-khan

NEET UG 2026 irregularities under investigation; NTA says full cooperation being extended to agencies
anam-khan

NEET UG 2026 Tie-Breaking Rule Explained: Here’s how ranks are decided
anam-khan

NEET 2026: Odisha aspirant dies by suicide fearing failure

Latest Question