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All electrons ejected from a surface by incident light of wavelength 200 \mathrm{~nm} can be stopped before travelling 1 \mathrm{~m} in the direction of uniform electric field of 4 \mathrm{~N} / \mathrm{C}. The work function of the surface is
 

Option: 1

4 \mathrm{eV}


Option: 2

6.2 \mathrm{eV}


Option: 3

2 \mathrm{eV}


Option: 4

2.2 \mathrm{eV}


Answers (1)

best_answer

The electron ejected with maximum speed \mathrm{v}_{\max } are stopped by electric field \mathrm{E}=4 \mathrm{~N} / \mathrm{C} after travelling distance \mathrm{d}=1 \mathrm{~m}.

\frac{1}{2} \mathrm{mv}^2=\mathrm{eEd}=4 \mathrm{eV}

The energy of incident photon = \frac{1240}{200}=6.2 \mathrm{eV}

From equation of photoelectric effect

\begin{aligned} & \frac{1}{2} \mathrm{mv}_{\max }^2=\mathrm{h\nu}-\phi_0 \\ & \therefore \quad \phi_0=6.2-4=2.2 \mathrm{eV} \end{aligned}

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