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Amount of energy (in cal) required to raise temprature of 5 g ice at 0^{0} C to water at 20^{0} C is (specific heat capacity of water = 1 cal / g ^{0}C   , latent heat of fusion  = 80 cal / g )

Option: 1 300

Option: 2 400

Option: 3 500

Option: 4 600

Answers (1)

best_answer

As we have learned  

Latent Heat -

Q = mL

- wherein

Q = heat supplied 

m = mass of substance

L = latent heat

 Q = m L + ms \Delta T

= 5 \times 80 cal + 5 \times 20 \times 1 = 500 cal

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