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  • An electric dipole is placed at an angle of 30° with an electric field of intensity <img alt="2 \times 10^5 \mathrm{NC}^{-1}" src="https://entrancecorner.oncodecogs.com/gif.latex?2%20%5Ctimes%2

An electric dipole is placed at an angle of 30° with an electric field of intensity 2 \times 10^5 \mathrm{NC}^{-1}. It experiences a torque equal to 4 Nm. Calculate the magnitude of charge on the dipole, if the dipole length is 2 cm.

Option: 1

\mathrm{8\, mC}


Option: 2

\mathrm{6\, mC}


Option: 3

\mathrm{4\, mC}


Option: 4

\mathrm{2\, mC}


Answers (1)

best_answer

\because \mathrm{q}=\frac{\tau}{\mathrm{dE} \sin \theta}=\frac{4}{0.02 \times 2 \times 10^5 \times \sin 30^{\circ}}=2 \times 10^{-3} \mathrm{C}=2 \mathrm{mc}

Posted by

Devendra Khairwa

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