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An electromagnetic wave of frequency \mathrm{\nu =3 \mathrm{MHz}} passes from vacuum into a dielectric medium with permittivity \mathrm{\varepsilon =4}. Then

 

Option: 1

wavelength and frequency both become half.
 


Option: 2

wavelength is doubled and frequency remains unchanged.
 


Option: 3

wavelength and frequency both remain unchanged.


Option: 4

wavelength is halved and frequency remains unchanged.


Answers (1)

best_answer

The frequency of electromagnetic wave remains unchanged
but the wavelength of electromagnetic wave changes when
it passes from one medium to another.

\begin{aligned} & c=\frac{1}{\sqrt{\mu_0 \varepsilon_0}} \\ \therefore \quad & c \propto \frac{1}{\sqrt{\varepsilon_0}} \text { and } v \propto \frac{1}{\sqrt{\varepsilon}} \\ \therefore \quad & \frac{c}{v}=\sqrt{\frac{\varepsilon}{\varepsilon_0}}=\sqrt{\frac{4}{1}}=2 ; \frac{c}{v}=\frac{\mathrm{v} \lambda}{\mathrm{v} \lambda^{\prime}}=\frac{\lambda}{\lambda^{\prime}}=2 \text { or } \lambda^{\prime}=\frac{\lambda}{2} \end{aligned}

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Anam Khan

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