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  • An electromagnetic wave of wavelength is incident on a photosensitive surface of negligible work function. If 'm' mass is of

An electromagnetic wave of wavelength '\lambda ' is incident on a photosensitive surface of negligible work function. If 'm' mass is of photoelectron emitted from the surface has de-Broglie wavelength \lambda _d then:

Option: 1

\lambda=\left ( \frac{2m}{hc} \right ) \lambda\: _ d\, ^2


Option: 2

\lambda _d=\left ( \frac{2mc}{h} \right ) \lambda ^2


Option: 3

\lambda=\left ( \frac{2mc}{h} \right ) \lambda\: _ d\, ^2

 


Option: 4

\lambda=\left ( \frac{2h}{mc} \right ) \lambda\: _ d\, ^2


Answers (1)

best_answer

Work Function\rightarrownegligible

                \phi \simeq 0

\frac{hc}{\lambda }=\phi +kE_{max}

\frac{hc}{\lambda }=0+\frac{P^{2}}{2m}=\frac{\left ( h/\lambda d \right )^{2}}{2m}

\frac{kc}{\lambda }=\frac{h}{\lambda ^{2}_{d}\times 2m}

\left ( \frac{2mc}{h} \right )\lambda ^{2}_{d}=\lambda

Posted by

Suraj Bhandari

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